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Question

The heat evolved during the combustion of 112 litre of water gas at SPT(mixture of equal volume of H2 and CO) is : Given
H2(g)+1/2O2(g)=H2O(g);△H=−241.8kJ
CO(g)+1/2O2(g)=CO2(g);△H=−283kJ

A
241.8 KJ
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B
283 KJ
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C
1312 KJ
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D
1586 KJ
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Solution

The correct option is B 1312 KJ
112 litre gas water {56lit.H256litCO
By combustion of
22.4 lit of H2241.8kJ
56 lit of H2241.8×5622.4
=604.5kJ
By combustion of 22.41CO2.83kJ
56 lit CO=283×5622.4
=707.5kJ
Total heat =707.5+604.5
=1.312kJ

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