The heat evolved in the combustion of benzene is given by C6H6l - 7 1 - 2 O2g- 3H2Ol - 6CO2g- - H - -781-0 Kcal mol -1When 156 g of C6H6 is burnt in an open container- the amount of heat energy released will be in kJ-mol

As given, C_6H_6(l) + 7 1 / 2 O_2(g)→ 3H_2O(l) + 6CO_2(g), Δ H = 781.0 #160;Kcal #160;mol^ 1 #160; #160; #160; 78 gm = 1 mol #160; 156/ 7 ...

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Combustion Reactions

The heat evol...

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The heat evolved in the combustion of benzene is given by
$C_{6} H_{6} (l) + 7 \frac{1}{2} O_{2} (g) \to 3 H_{2} O (l) + 6 C O_{2} (g), Δ H = - 781.0 K c a l m o l^{- 1}$
When $156 g o f C_{6} H_{6}$ is burnt in an open container, the amount of heat energy released will be (in kJ/mol)

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C_{6} H_{6 (l)} + \frac{15}{2} O_{2 (g)} \to 6 C O_{2 (g)} + 3 H_{2} O_{(l)}, Δ H = - 3264

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C_{6} H_{6 (l)} + \frac{15}{2} O_{2 (g)} \to 3 H_{2} O_{(i)} + 6 C O_{2 (g)}

Δ H = - 3264.4 k J / m o l

25^{o} C

C_{6} H_{6} (l) + \frac{15}{2} O_{2} (g) \to 6 C O_{2} (g) + 3 H_{2} O (l)

Δ H = - 780980 c a l

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C_{6} H_{6 (l)} + 7 \frac{1}{2} O_{2 (g)} \to {6 C O}_{2 (g)} + {3 H}_{2} O_{(l)}

{m o l}^{- 1}

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