The heat for a reaction, C10H8(s)+12O2(g)→10CO2(g)+4H2O(l)
at constant volume is given as −1228.2kcal at 25oC. The heat of the reaction at constant pressure and same temperature is:
A
−1345.5kcal
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B
−1229.3kcal
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C
−1156kcal
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D
−1380.2kcal
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Solution
The correct option is B−1229.3kcal Given that, △U=−1228.2kcal=−1228.2×103cal
we know that: △H=△U+△ngRT △ng=10−12=−2 T=25+273=298K R=2cal/K.mol
so, △H=−1228.2×103+(−2)×(2)×298=−1229.39kcal