The heat generated through 4 - and 9 - resistances separately- when a capacitor of 100 - F capacity charged to 200 V is discharged one buy one- will be

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Standard XII

Physics

EMF and EMF Devices

The heat gene...

Question

The heat generated through $4 Ω$ and $9 Ω$ resistances separately, when a capacitor of $100 μ F$ capacity charged to 200 V is discharged one buy one, will be

2 J and 8 J, respectively

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8 J and 2 J, respectively

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2 J and 4 J, respectively

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2 J and 2 J, respectively

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Solution

The correct option is D 2 J and 2 J, respectively
We know that heat generated $=$ energy stored in the capacitor.
Here heat generated through each resistor is $H = \frac{1}{2} C V^{2} = \frac{1}{2} \times 100 \times 10^{- 6} \times (200)^{2} = 2 J$

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Similar questions

Q. An ideal gas is made to go through a cyclic thermodynamic process in four steps. The amount of heat involved are

Q_{1} = 600 {J, Q}_{2} = - 400 {J, Q}_{3} = - 300 {J and Q}_{4} = 200 J

respectively. The corresponding work involved are

W_{1} = 300 {J, W}_{2} = - 200 {J, W}_{3} = - 150 {J and W}_{4}

.
What is value of

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Q. An ideal gas is taken through a cyclic thermodynamic process through four steps

1, 2, 3, 4

respectively. The amounts of heat involved in these steps are

Q_{1} = 5960 J, Q_{2} = 5585 J, Q_{3} = - 2980 J

and

Q_{4} = 3645 J

respectively. The corresponding quantities of work involved are

W_{1} = 2200 J, W_{2} = 8250 J, W_{3} = - 1100 J

and

W_{4}

respectively. The value of

W_{4}

An ideal gas is taken through a cyclic thermodynamical process through four steps $Q_{1}$ = 5960J, $Q_{2}$ = –5585J, $Q_{3}$ = –2980J and $Q_{4}$ = 3645J, respectively. The corresponding works involved are $W_{1} = 2200 J, W_{2} = - 825 J, W_{3} = - 1100 J$ and $W_{4}$ respectively. The value of W4 is:

Q.
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C_{1} a n d C_{2}

are 120mC and 180mC respectively. In another arrangement, the same capacitors

C_{1} a n d C_{2}

are completely discharged and then connected with the same batteries along with a switch ‘S’ as shown in figure 2.

The total work done by both the batteries (W) and the heat dissipated in the circuit (H) after the switch is shorted are respectively,

Q. An ideal gas is taken through a cyclic thermodynamic process through four steps. The amount of heat exchanged in the steps are

Q_{1} = + 5960 J, Q_{2} = - 5600 J, Q_{3} = - 3000 J, Q_{4} = + 3600 J

respectively. The corresponding quantities of internal energy changes are

Δ U_{1} = + 3760 J, Δ U_{2} = - 4800 J, Δ U_{3} = - 1800 J

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The heat generated through 4Ω and 9Ω resistances separately, when a capacitor of 100μF capacity charged to 200 V is discharged one buy one, will be

The correct option is D 2 J and 2 J, respectivelyWe know that heat generated = energy stored in the capacitor.Here heat generated through each resistor is H=12CV2=12×100×10−6×(200)2=2J

The heat generated through $4 Ω$ and $9 Ω$ resistances separately, when a capacitor of $100 μ F$ capacity charged to 200 V is discharged one buy one, will be

The correct option is D 2 J and 2 J, respectively
We know that heat generated $=$ energy stored in the capacitor.
Here heat generated through each resistor is $H = \frac{1}{2} C V^{2} = \frac{1}{2} \times 100 \times 10^{- 6} \times (200)^{2} = 2 J$