Question

The heat loss from a fin is $6W.$ The effectiveness and efficiency of the fin are $3$ and $0.75$ respectively. The heat loss (in $W$) from the fin. Keeping the entire fin surface at base temperature is

Answer 1

$q_{actual}$ from fin $=6watt$
${\eta }_{fin}=\frac{q_{actual}}{q_{max.possible}}$i.e. when entire fin at base temperature
$\therefore$ $q$ from fin if entire fin at base temperature
$=\frac{q_{act.}}{0.75}=\frac{6}{0.75}=8W$