wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The heat of atomisation of PH3(g) is 228kcalmol1 and that P2H4(g) is 355kcalmol1 . The energy of the PP bond is (in kcal):

A
102
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
51
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
26
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
204
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 51
The balanced chemical equation for the atomization of phosphine is PH3P+3H;ΔH=228
epH=2283
The balanced chemical equation for the atomization of P2H4(g) is H2PPH22P+4H;ΔH=355
epp+4×epH=355
epp+4×2283=355
epp=51
The energy of the PP bond is 51 kcal.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Buffer Solutions
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon