The heat of atomisation of PH3(g) is 228kcalmol−1 and that P2H4(g) is 355kcalmol−1 . The energy of the P−−P bond is (in kcal):
A
102
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B
51
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C
26
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D
204
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Solution
The correct option is B 51 The balanced chemical equation for the atomization of phosphine is PH3⟶P+3H;ΔH=228 ep−−H=2283 The balanced chemical equation for the atomization of P2H4(g) is H2P−−PH2⟶2P+4H;ΔH=355 ep−−p+4×ep−−H=355 ep−−p+4×2283=355 ep−−p=51 The energy of the P−−P bond is 51 kcal.