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Properties of Enthalpy

The heat of a...

Question

The heat of atomization of a compound $X Y_{3}$ in gaseous state is $E k J m o l^{- 1}$ . What is the bond energy of $X - Y$ bond in $k J m o l^{- 1}$ unit?

A

E

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B

3 E

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C

\frac{E}{3}

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D

\frac{E}{6}

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Solution

The correct option is C $\frac{E}{3}$
Given, the heat of atomization of a compound $X Y_{3}$ in gaseous state is $E k J m o l^{- 1}$ .
$∴ X Y_{3} (g) \to X (g) + 3 Y (g); Δ H = E k J m o l^{- 1}$
Hence Bond energy of $X - Y$ bond = $\frac{E}{3}$ , as $X Y_{3}$ contains three $X - Y$ bonds.

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Q. What is the heat of formation of liquid methyl alcohol in

k J m o l^{- 1},

use the following data.
Heat of vaporization of liquid methyl alcohol =

38 k J m o l^{- 1}

.
Heat of formation of gaseous atoms from the elements in their standard states:

H = 218 k J m o l^{- 1}, C = 715 k J m o l^{- 1}, O = 249 k J m o l^{- 1}

Average bond energies :

C - H = 415 k J m o l^{- 1} C - O = 356 k J m o l^{- 1} O - H = 463 k J m o l^{- 1}

Q. What is the heat of formation of liquid methyl alcohol in

k J m o l^{- 1},

use the following data.
Heat of vaporization of liquid methyl alcohol =

38 k J m o l^{- 1}

.
Heat of formation of gaseous atoms from the elements in their standard states:

H = 218 k J m o l^{- 1}, C = 715 k J m o l^{- 1}, O = 249 k J m o l^{- 1}

Average bond energies :

C - H = 415 k J m o l^{- 1} C - O = 356 k J m o l^{- 1} O - H = 463 k J m o l^{- 1}

Q. Compute the heat of formation of liquid methyl alcohol (in kJ mol

^{- 1}

) using the following data. The heat of vaporisation of liquid methyl alcohol is 38 kJ mol

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The heat of formation of gaseous atoms from the elements in their standard states:

H =

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Average bond energies:

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C - O = 356

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O - H = 463

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