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Nucleophilic Substitution Reaction

THE HEAT OF C...

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THE HEAT OF COMBUSTION OF BENZENE AT 27 DEGREE C FOUND BY BOMB CALORIMETER C6H6+ 15/2 O2 GIVES 6CO2 +3H2O IS 780 kcal /mol .WHAT WILL BE THE HEAT EVOLVED IN BURNING 39g OF BENZENE IN AN OPEN VESSEL ?

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Similar questions

Q. The heat of combustion of benzene at

27^{\circ} C

found by bomb calorimeter i.e. for the reaction

C_{6} H_{6 (l)} + 7 \frac{1}{2} O_{2 (g)} \to {6 C O}_{2 (g)} + {3 H}_{2} O_{(l)}

{m o l}^{- 1}

. The heat evolved on burning 39g of benzene in an open vessel will be

Q. The heat of combustion of benzene is

- 3264 k J m o l^{- 1}

. The heat evolved in the combustion of

39 g

of benzene will be

Q. The heat of combustion of benzene in a bomb calorimeter (i.e., constant volume) was found to be

3263.9 k J m o l^{- 1}

25^{o} C

. Calculate the heat of combustion of benzene at constant pressure.

Q. The heat of combustion of benzene in a bomb calorimeter (i.e., constant volume) was found to be

3263.9 k J m o l^{- 1}

25^{o} C

. Calculate the heat of combustion of benzene at constant pressure.

Q. Type: Multiple Correct answers
The heat evolved in the combustion of benzene is given by
C₆H₆(l)+15/2O₂(g)----------->3H₂O(l)+6CO₂(g)
∆H=-781.0kcal mol^-1When 156 g of C₆H₆ is burnt in an open container the amount of heat energy released will be
a)150.2 kcal mol^-1 b)1562.0 kcal mol^-1
c)6528.2 kJ mol-1^-1 d)2448.5 kJ mol^-1

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