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Calorimetry

The heat of c...

Question

The heat of combustion of ethanal determined in a bomb calorimeter is $- 670.48 K$ Cals ${m o l e}^{- 1}$ at $25^{o} C$ .What is $Δ H$ at $25^{o} C$ for the reaction:

- 335.24 K C a l s .

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- 671.08 K C a l s .

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- 670.48 K C a l s .

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+ 670.48 K C a l s .

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Solution

The correct option is C $- 670.48 K C a l s .$
Given $Δ H_{c o m b u s t i o n} (C H_{3} C H O) = - 670.48$ $K c a l s m o l^{-}$
$C H_{3} C H O + 3 O_{2} ⟶ 2 C O_{2} + 2 H_{2} O$

$Δ H_{r e a c t i o n} = \sum Δ H_{c o m b u s t i o n}^{r e a c t a n t} - \sum Δ H_{c o m b u s t i o n}^{p r o d u c t}$

$Δ H_{r e a c t i o n} = Δ H_{c o m b u s t i o n}^{C H_{3} C H O} + 3 \times 0 - 2 \times 0 - 2 \times 0$

$= - 670.48$ $K c a l s m o l^{-}$

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