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Question

The heat of combustion of ethanol determined by a bomb calorimeter is 670.48kcalmol1 at 250C. What is ΔU250C for the following reaction?

C2H5OH(l)+72O2(g)2CO2(g)+3H2O(g)

A
-335.24 kcal
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B
-669.28 kcal
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C
-670.48 kcal
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D
+670.48 kcal
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Solution

The correct option is A -335.24 kcal
ΔH=ΔE+ngRT
ΔE=ΔHngRT
ΔE=670.48+2×2×298=335.24Kcal

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