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Question

The heat of formation of C2H5OH(l) is 66 kcal mol1. The heat of combustion of CH3OCH3 (g) is 348 kcal mol1. Hf for H2O and CO2 are 68 kcal mol1 and 94 kcal mol1 respectively.
Then, the H for reaction C2H5OH(l)CH3OCH3(g) is :

A
H=18 kcal mol1
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B
H=22 kcal mol1
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C
H=26 kcal mol1
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D
H=30 kcal mol1
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Solution

The correct option is B H=22 kcal mol1
HofC2H5OH(l)=66kcal/mol
2C(s)+12O2(g)+3H2(g)C2H5OH(l)
H1=66 kcal mol1 ....(1)

CH3OCH3(g)+3O2(g)2CO2(g)+3H2O(l) H2=348 kcal mol1 ...(2)

H2(g)+12O2(g)H2O(l) H3=68 kcal mol1 ...(3)

C(s)+O2(g)CO2(g) H4=94 kcal mol1 ....(4)

Then for reaction,
C2H5OH(l)CH3OCH3(g)

This reaction can be obtained by the combination,
Target equation = - eq.(1) - eq.(2) + 3 [eq.(3)] + 2 [eq.(4)]
So, H for the above isomerisation reaction can be obtained by ;

H=+66+3483×682×94=+66+348204188

H=22 kcal mol1

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