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Byju's Answer

Standard XII

Chemistry

Introduction to Alkenes

The heat of h...

Question

The heat of hydrogenation of one double bond in cyclohexene is 28.6kcal ${m o l}^{- 1}$ and the heat of hydrogenation of benzene to cyclohexane is 50kcal ${m o l}^{- 1}$ . What will be the resonance stabilization energy of benzene?

28.6 kcal

{m o l}^{- 1}

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55.0 kcal

{m o l}^{- 1}

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85.8 kcal

{m o l}^{- 1}

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35.8 kcal

{m o l}^{- 1}

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Solution

The correct option is C 35.8 kcal ${m o l}^{- 1}$
Resonance Energy = Calculated Heat of Hydrogenation-Practical Heat of Hydrogenation
$= (28.6 \times 3 - 50) K c a l m o l^{- 1}$
$= 35.8 K c a l m o l^{- 1}$

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Similar questions

Q. Bond dissociation energy of

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103 k c a l m o l^{- 1}

and heat of formation of

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Cyclohexene H_{2} - \to N i Cyclohexane; Δ H = - 28.6 kcal/mol

Anthracene H_{2} - \to N i Tetradecahydroanthracene; Δ H = - 116.2 kcal/mol

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Q. Standard heat of formation of

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I E (K) = 4.3 e V

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Bond dissociation energy of

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Q. Bond dissociation energy of

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103 k c a l / m o l .

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The heat of hydrogenation of one double bond in cyclohexene is 28.6kcal mol−1 and the heat of hydrogenation of benzene to cyclohexane is 50kcal mol−1. What will be the resonance stabilization energy of benzene?

The correct option is C 35.8 kcal mol−1Resonance Energy = Calculated Heat of Hydrogenation-Practical Heat of Hydrogenation=(28.6×3−50)Kcal mol−1=35.8Kcal mol−1

The heat of hydrogenation of one double bond in cyclohexene is 28.6kcal ${m o l}^{- 1}$ and the heat of hydrogenation of benzene to cyclohexane is 50kcal ${m o l}^{- 1}$ . What will be the resonance stabilization energy of benzene?

The correct option is C 35.8 kcal ${m o l}^{- 1}$
Resonance Energy = Calculated Heat of Hydrogenation-Practical Heat of Hydrogenation
$= (28.6 \times 3 - 50) K c a l m o l^{- 1}$
$= 35.8 K c a l m o l^{- 1}$