The heat of neutralization is the change in enthalpy that occurs when one equivalent of an acid and one equivalent of a base undergo a neutralization reaction to form water and a salt. Heat of neutralization of strong acid with strong base is −13.7 kcal mol−1.
List - IList - II(|Enthalpy change in kcal|)(Neutralisation)(I) < 13.7 kcal(P) HCl1 mol+NaOH1 mol(II) = 13.7 kcal(Q) HF1 mol+NaOH1 mol(III) > 13.7 kcal(R) HCl1 mol+NH4OH1 mol(IV) = 27.4 kcal(S) NaOH2 mol+H2SO41 mol(T) NaOH1 mol+CH3COOH1 mol
Which of the following options has the correct combination considering List-I and List-II?