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Question

The heat of neutralization of a strong base and a strong acid is 13.7 kcal. The heat released when 0.6 mole HCl solution is added to 0.25 mole of NaOH is:

A
3.425 kcal
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B
8.22 kcal
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C
11.645 kcal
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D
13.7 kcal
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Solution

The correct option is A 3.425 kcal
HCl1 mole+NaOH1 moleNaCl+H2O ΔH=13.7 Kcal

HCl0.25 mole+NaOH0.6 moleNaCl+H2O

Here HCl is the limiting reagent.

0 0.60.25 0.25mole

Then, release energy =13.7×0.25=3.425 Kcal

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