Question

The heat of neutralization of a strong base and a strong acid is $13.7$ kcal. The heat released when $0.6$ mole HCl solution is added to $0.25$ mole of NaOH is:

• A. $3.425$ kcal
• B. $8.22$ kcal
• C. $11.645$ kcal
• D. $13.7$ kcal

Answer 1

The correct option is A $3.425$ kcal

$\underset{1mole}{HCl}+\underset{1mole}{NaOH}\to NaCl+H_{2}O$ $\Delta H=-13.7$ Kcal

$\underset{0.25mole}{HCl}+\underset{0.6mole}{NaOH}\to NaCl+H_{2}O$

Here HCl is the limiting reagent.

$0$ $0.6-0.25$ $0.25$mole

Then, release energy $=13.7\times 0.25=3.425Kcal$