The heat of neutralization of a strong base and a strong acid is 57 kJ. The heat released, when 0.5 mole of $H N O_{3}$ solution is added to 0.20 moles of NaOH solution, is:

11.4 kJ

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34.7 kJ

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23.5 kJ

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58.8 kJ

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Solution

The correct option is A
11.4 kJ

0.2 mole of $H N O_{3}$ are neutralized by 0.2 mole of NaOH to give heat = $57 \times 0.2 = 11.4 k J$

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The heat of neutralization of a strong base and a strong acid is 57 kJ. The heat released, when 0.5 mole of HNO3 solution is added to 0.20 moles of NaOH solution, is:

The correct option is A 11.4 kJ 0.2 mole of HNO3 are neutralized by 0.2 mole of NaOH to give heat =57×0.2=11.4kJ

The heat of neutralization of a strong base and a strong acid is 57 kJ. The heat released, when 0.5 mole of $H N O_{3}$ solution is added to 0.20 moles of NaOH solution, is:

The correct option is A
11.4 kJ

0.2 mole of $H N O_{3}$ are neutralized by 0.2 mole of NaOH to give heat = $57 \times 0.2 = 11.4 k J$