The correct option is A 40%
Given, heat rejected(Q2) per cycle is 60% of the heat supplied(Q1
⇒Q2=0.6 Q1
From conservation of energy on heat engine,
⇒Q1=Q2+W
W=Q1−Q2
⇒W=Q1−0.6Q1=0.4Q1
Substituting W in the formula of efficiency we get,
η=WQ1×100
∴η=0.4Q1Q1×100=40%