Question

The heat released in neutralisation of HCl and NaOH is 13.7 k cal/mol, the heat released on neutralisation of NaOH with $C{H}_{3}COOH$ is 3.7 k cal/mol. The $\Delta H^{\circ }$ of ionisation of $C{H}_{3}COOH$ is

• A. 10.2 k cal
• B. 10 k cal
• C. 3.7 k cal
• D. 9.5 k cal

Answer 1

The correct option is B 10 k cal

$HCl+NaOH\to NaCl+H_{2}O,\Delta H=-13.7kcal/mol$
Heat of ionisation of $C{H}_{3}COOH$ is:
$13.7-\left(3.7\right)=10kcal/mol$