The heat required (in cal) to change 10 g ice at 0oC to steam at 100oC is ( Heat of fusion and heat of vaporization for H2O are 80 cal/g and 540 cal/g respectively. Specific heat of water is 1 cal/g)
A
6500
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B
7200
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C
5400
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D
6000
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Solution
The correct option is B 7200
The heat required for the melting of ice is 10×80=800cal
The heat required for evaporation of water is 10×540=5400
The heat required for changing the temperature of water from 00C to 1000C is 10×1×100=1000cal
Total heat required for the entire process is 800+5400+1000=7200cal