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Question

The heats of neutralisation of CH3COOH, HCOOH, HCN and H2S are -12.8, -13.2, -3.2 and -3.9 kcal per equivalent. Arrange these acids in increasing order of strength.


A

H2S<HCN<HCOOH<CH3COOH

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B

HCN<H2S<CH3COOH<HCOOH

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C

HCOOH<CH3COOH<H2S<HCN

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D

CH3COOH<HCOOH<HCN<H2S

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Solution

The correct option is B

HCN<H2S<CH3COOH<HCOOH


Heat of neutralization per equivalent Acidic strength, the maximum value being the enthalpy of formation of water. Every equivalent of an acid would form 1 mole of water if it were a strong acid. As an acid gets weaker, this value decreases as fewer water molecules are formed - as fewer protons are furnished by weaker acids.


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