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Ionisation Energy

The heavier s...

Question

The heavier stable nuclei tend to have larger N/Z ratio because

A

A neutron is heavier than a proton

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B

A neutron is an unstable particle

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C

A neutron does not exert electric repulsion

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D

Coulomb forces have longer range compared to nuclear forces

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Solution

The correct options are
C A neutron does not exert electric repulsion
D Coulomb forces have longer range compared to nuclear forces
As the number of protons increases, Coulomb repulsive among protons increases. To compensate this repulsion, number of neutrons is increased.

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Similar questions

Q. The heavier nuclei tend to have larger N/Z ratio because
(a) a neutron is heavier than a proton
(b) a neutron is an unstable particle
(c) a neutron does not exert electric repulsion
(d) Coulomb forces have longer range compared to the nuclear forces.

Q. A free neutron decays to a proton but a free proton does not decay to a neutron. This is because
(a) neutron is a composite particle made of a proton and an electron whereas proton is a fundamental particle
(b) neutron is an uncharged particle whereas proton is a charged particle
(c) neutron has large rest mass than the proton
(d) weak forces can operate in a neutron but not in a proton.

Q. The heavier nuclei tend to have larger N/Z ratio because

Q. Inspite of mutual repulsion between the protons and no electric force between neutrons, a number of protons and neutrons do stay together to form stable nuclei. Which of the following are reasons for this?

1

. Another type of force, called nuclear force works between these particles when they are very close to each other

2

. The neutrons keep the protons apart so that there is no repulsion between them

3

. The nuclear force is always attractive and does not depend on the charge of the particles
Select the correct answer from the codes given.

Q. STATEMENT-1:
The plot of atomic number (y-axis) versus number of neutrons (x-axis) for stable nuclei shows a curvature towards x-axis from the line of

45^{o}

slope as the atomic number is increased.
STATEMENT-2:
Proton-proton electrostatic repulsions begin to overcome attractive forces involving protons and neutrons and neutrons in heavier nuclides.

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