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Question

The height at which the acceleration due to gravity becomes g9 (where g = the acceleration due to gravity on the surface of th earth) in terms of R, radius of the earth is

A
2R
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B
R3
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C
R2
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D
2R
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Solution

The correct option is A 2R
Acceleration due to gravity at height h g=GM(R+h)2
Acceleration due to gravity on surface of earth g=GMR2
Where R= radius of earth.
gg=(RR+h)2
As g=g9 we get
g9g=(RR+h)2
19=(RR+h)2RR+h=13
3R=R+h2R=h

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