GivenLength of cuboid ( 1)=12cm Breadth (b)=9cm
and Height (h)=5cm
Total surface area of cuboid =2(lb+bh+hl)
=2[(12×9)+(9×5)+(5×12)]
=2[108+45+60]
2×213=426cm2
Volume =l×b×h
=12×9×5=540cm3
Hence, total surface area of cuboid 426cm2
And volume of the cuboid 540cm3