The height of a conical tent is $14 m$ and its floor area is $346.5 m^{2}$ . The length of canvas, $1.1 m$ wide, required for it is:

490 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

525 m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

665 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

860 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $525 m$
Surface area of the base $= π r^{2} = 346.5 \Rightarrow r^{2} = (\frac{3465}{10} \times \frac{7}{22})$
$= \frac{441}{4} = (\frac{21}{2})^{2} \Rightarrow r = \frac{21}{2} m$
$l = \sqrt{r^{2} + h^{2}} = \sqrt{\frac{441}{4} + (14)^{2}} = \sqrt{\frac{1225}{4}} = \frac{35}{2} m$
$A r e a o f c a n v a s = π r l$
$= (\frac{22}{7} \times \frac{21}{2} \times \frac{35}{2}) m^{2} = 577.5 m^{2}$
$L e n g t h o f c a n v a s = \frac{A r e a}{W i d t h} = \frac{557.50}{1.1} m = 525 m$ .

Suggest Corrections

Similar questions

The height of a conical tent is 14 m and its floor area is 346.5 $m^{2}$ . How much canvas, 1.1 m wide, will be required for it ?

(a) 490 m (b) 525 m (c) 665 m (d) 860 m

1.1

14

346.5 m^{2}

154

24

The volume of a conical tent is 1232 $m^{3}$ and the area of the base floor is 154 $m^{2}$ . Calculate the :

(i) radius of the floor,

(ii) height of the tent,

(iii) length of the canvas required to cover this conical tent if its width is 2 m.

Join BYJU'S Learning Program