Question

The height of a tower is $50\sqrt{3}m$. The angle of elevation of a tower from a distance $50m$ from its feet is

• A. ${30}^{\circ }$
• B. ${45}^{\circ }$
• C. ${60}^{\circ }$
• D. ${90}^{\circ }$

Answer 1

The correct option is C ${60}^{\circ }$

It is given that the height of the tower is $50\sqrt{3}\text{m}$ and the distance of the tower from the point is $50\text{m}$.

Representing this through a diagram.

Now, In $△ABC$,

$\tan \theta =\frac{50\sqrt{3}}{50}=\sqrt{3}$
$\theta ={60}^{\circ }$.