The height of a tree is 10√3 m, if a boy looks at the top of the tree with an angle of elevation of 30∘, find the distance between the boy and the tree.
30 m
The given figure illustrates the scenario mentioned in the question :
Given, the tree is having a height of 10√3 m.
So, AB = 10√3 m.
In Triangle ABC,
tan30∘=ABBC=1√3⇒BC=10√3×√3⇒BC=30 m.