The height of a wall is six times its width and the length of the wall is seven times its height. If volume of the wall be 16128 cu. m, its width is -

4 m

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4.5 m

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5 m

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6 m

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9 m

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Solution

The correct option is A
4 m

Let the width of the wall be `x' metres

Then, height = (6x) metres and length = (42x) metres

$∴$ (42x) $\times$ (x) $\times$ (6x) = 16128 $\Leftrightarrow$ x $^{3}$ = $(\frac{16128}{42 \times 6})$ = 64 $\Leftrightarrow$ x=4

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The height of a wall is six times its width and the length of the wall is seven times its height. If volume of the wall be 16128 cu. m, its width is -

The correct option is A 4 m Let the width of the wall be `x' metres Then, height = (6x) metres and length = (42x) metres ∴ (42x) × (x) × (6x) = 16128 ⇔ x3 =(1612842×6) = 64 ⇔x=4

The correct option is A
4 m

Let the width of the wall be `x' metres

Then, height = (6x) metres and length = (42x) metres

$∴$ (42x) $\times$ (x) $\times$ (6x) = 16128 $\Leftrightarrow$ x $^{3}$ = $(\frac{16128}{42 \times 6})$ = 64 $\Leftrightarrow$ x=4