Question

The height of an equilateral triangle is 3$\sqrt{3}$ cm. Its area is

(a) 6$\sqrt{3}c{m}^2$ (b) 27$c{m}^2$ (c) 9$\sqrt{3}c{m}^2$ (d) 27$\sqrt{3}c{m}^2$

Answer 1

In Equilateral Triangle

Height = (side of triangle) $\times \frac{\sqrt{3}}{2}$

Let the side of triangle be a

Hence

$3\sqrt{3}=a\times \frac{\sqrt{3}}{2}$

a = 6cm

Area of Equilateral Triangle = $Height\times \frac{Base}{2}$

$=3\sqrt{3}\times \frac{6}{2}$

$=9\sqrt{3}c{m}^2$