The height of figure A is $9 feet$ . The height of a familiar figure B is $15 feet$ . What is the value of the ratio of the perimeter of A to the perimeter of B?

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Solution

Find the ratio of the perimeter of figure A to the perimeter of figure B.
Given, the height of figure of A is $9 feet$ .
And, the height of a similar figure B is $15 feet$
Since, when two figures are similar then the value of the ratio of their perimeter is equal to the value of the ratio of their corresponding side lengths.
$\Rightarrow \frac{P e r i m e t e r o f f i g u r e A}{P e r i m e t e r o f f i g u r e B} = \frac{H e i g h t o f f i g u r e A}{H e i g h t o f f i g u r e B}$
So, the ratio of the perimeter of A to B is,
$\Rightarrow \frac{P e r i m e t e r o f f i g u r e A}{P e r i m e t e r o f f i g u r e B} = \frac{9}{15} = \frac{3}{5}$
Hence, the ratio of the perimeter of figure A to the perimeter of figure B is $\frac{3}{5}$ .

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