The height of the building is 200\sqrt{3}ft, What is the angle of elevation from a point on the level ground 100ft away from the base of the building?

$60^{\circ}$

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$30^{\circ}$

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$50^{\circ}$

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$70^{\circ}$

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Solution

The correct option is A
$60^{\circ}$

Tan(angle of elevation) = \frac{height~of~the~building}{Distance~from~the~base~of~the~building}

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The angle of elevation of the rope of a tree from a point A on the ground is $60^{\circ}$ . On walking 20m away from its base to a point B, the angle of elevation changes to $30^{\circ}$ . Find the height of the tree.

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The height of the building is 200\sqrt{3}ft, What is the angle of elevation from a point on the level ground 100ft away from the base of the building?

The correct option is A 60∘ Tan(angle of elevation) = \frac{height~of~the~building}{Distance~from~the~base~of~the~building}

The correct option is A
$60^{\circ}$

Tan(angle of elevation) = \frac{height~of~the~building}{Distance~from~the~base~of~the~building}