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Question


The height of the tower(AB) is

A
53 m
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B
10 m
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C
103 m
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Solution

The correct option is C 103 m
Here, AB is the height of the tower and BC is the width of canal.
CD = 20 m
As per question,
In right ΔABD,
tan 30=ABBD
13=AB(20+BC)
AB=(20+BC)3...(i)
Also,
In right ΔABC,
tan 60=ABBC
3=ABBC
AB=3BC...(ii)
From equation (i) and (ii)
AB=3BC=(20+BC)3
3BC=20+BC
2BC=20BC=10m
Putting the value of BC in equation (ii)
AB=103m
Thus, the height of the tower is 103 m.

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