The heights of two buildings are 34m and 29m respectively. If the distance between the two building is 12m, find the distance between the top of the buidings.
The vertical buildings AB and CD are 34m and 29m respectively.
Draw DE ⊥ AB.
Then AE=AB–EB but EB=DC
Now, AED is a right angled triangle and right angled at E.
Therefore the distance between the top of the buidings. is 13m