The height of the water in a tank is H. The range of the liquid emerging out from a hole in the wall of the tank at a depth 3H4 from the upper surface of water, will be
A
H
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B
H2
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C
3H2
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D
√3H2
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Solution
The correct option is D√3H2
Given:
h′=3H4
h=H−3H4=H4
horizontal range of the liquid coming out a hole R=2√hh′
where
h= depth of the hole below the free surface of the liquid
h′= height of the hole above the bottom of the tank