The height of tower is $100 m$ find the distance from tower to a point where the angle of depression from top of tower is $30^{\circ}$

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Solution

The height of tower is $100 m$

The angle of depression $= 30^{\circ}$

The distance from tower is

$tan 30 = \frac{d i s t a n c e}{H e i g h t}$

$\frac{1}{\sqrt{3}} = \frac{D i s t a n c e}{100}$

$D i s t a n c e = \frac{100}{\sqrt{3}} m$

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The height of tower is 100m find the distance from tower to a point where the angle of depression from top of tower is 30∘

The height of tower is 100mThe angle of depression =30∘The distance from tower is tan30=distanceHeight1√3=Distance100Distance=100√3m

The height of tower is $100 m$ find the distance from tower to a point where the angle of depression from top of tower is $30^{\circ}$

The height of tower is $100 m$

The angle of depression $= 30^{\circ}$

The distance from tower is

$tan 30 = \frac{d i s t a n c e}{H e i g h t}$

$\frac{1}{\sqrt{3}} = \frac{D i s t a n c e}{100}$

$D i s t a n c e = \frac{100}{\sqrt{3}} m$