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Equation of Motion of Free Fall

The height wh...

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The height which the acceleration due to gravity is reduced to one fourth of the gravity on the surface of the Earth is

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Q. The height from earth's surface at which acceleration due to gravity becomes

\frac{g}{4}

g

is acceleration due to gravity on the surface of earth and

R

is radius of earth).

Q. The ratio of acceleration due to gravity at a height

3 R

above earth's surface to the acceleration due to gravity on the surface of the earth is (

R =

radius of earth):

Q. If R is the radius of the earth, then the ratio of acceleration due to gravity on surface of the earth to acceleration due to gravity at height nR is:

Q. At what height

^{'} h^{'}

from the earth surface, acceleration due to gravity becomes half as that of acceleration due to gravity on the surface of earth.
[

R

= Radius of earth]

The acceleration due to gravity becomes g/2 (g= acceleration due to gravity on the surface of earth) at a height equal to

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Equation of Motion of Free Fall

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