wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The height y and distance x along the horizontal plane of a projectile on a certain planet are given y=8t−5t2 (mtr) and x=6t (mtr). The acceleration due to gravity is:

A
10 m/s2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
5 m/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
20 m/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2.5 m/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 10 m/s2
x=uxT
equation of projectile path
y=8t5t2Vy=dydt=810tay=d2ydt2=10 m/s2

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Basketball
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon