Question

The height y and distance x along the horizontal plane of a projectile on a certain planet are given $y=8t-5t^2\left(mtr\right)$ and $x=6t\left(mtr\right)$. The acceleration due to gravity is:

• A. $10m/s^2$
• B. $5m/s^2$
• C. $20m/s^2$
• D. $2.5m/s^2$

Answer 1

The correct option is A $10m/s^2$

$x=u_{x}T$
equation of projectile path
$y=8t-5t^2{V}_y=\frac{dy}{dt}=8-10t{a}_y=\frac{d^{2}y}{d{t}^2}=-10m/s^2$