Question

# The height $$y$$ and horizontal distance $$x$$ covered by a projectile in a time $$t$$ seconds are given by the equations $$y=8t-{ 5t }^{ 2 }$$ and $$x=6t$$. If $$x$$ and $$y$$ are measured in metres, the velocity of projection is:

A
8 ms1
B
6 ms1
C
14 ms1
D
10 ms1

Solution

## The correct option is D $$10\ { ms }^{ -1 }$$$$x=6t$$on differentiating with respect to t$$v_x=6$$$$y=8t-5t^2$$$$v_y=8-5t$$at t=0 $$v_y=8$$$$v^2=6^2+8^2=10^2$$$$v=10m/s$$Physics

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