The heights (in cm ) of 40 boys were measured and recorded and under:

Height (in cm) 165 170 175 180

Number of boys 9 8 11 12

Find the mean height.

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Solution

Mean height = $\frac{Σ (f_{i} \times x_{i})}{Σ f_{i}} = \frac{6930}{40} = 173.25 cm$

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Similar questions

Heights of students of Class X are given in the foloowing frequency distribution:

Height (in cm)	150−155	155−160	160−165	165−170	170−175
Number of students	15	8	20	12	5

Find the modal height.
Also, find the mean height. Compare and interpret the two measures of central tendency. [CBSE 2014]

Calculate the median from the following data:

$\begin{matrix} Height (in cm) & 135 - 140 & 140 - 145 & 145 - 150 & 150 - 155 & 155 - 160 & 160 - 165 & 165 - 170 & 170 - 175 Number of days & 6 & 10 & 18 & 22 & 20 & 15 & 6 & 3 \end{matrix}$

Q. Find the values of a, b, c, d, e, f, g from the following frequency distribution of the heights of 50 students in a class:

Height (in cm)	Frequency	Cumulative frequency
160 – 165	15	a
165 – 170	b	35
170 – 175	12	c
175 – 180	d	50
180 – 185	e	55
185 – 190	5	f
	g

Q. The heights (in cm) of 90 plants in a garden are given below:

Height (in cm)	58	60	62	64	66	74
Number of plants	20	25	15	8	12	10

Find the mean height.

Q. Consider the frequency distribution of the heights of 60 students of a class

Height (in cm)	No. of Students	Cumulative Frequency
150-155	16	16
155-160	12	28
160-165	9	37
165-170	7	44
170-175	10	54
175-180	6	60

The sum of the lower limit of the modal class and the upper limit of the median class is
(a) 310
(b) 315
(c) 320
(d) 330

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The heights (in cm ) of 40 boys were measured and recorded and under: Height (in cm) 165 170 175 180 Number of boys 9 8 11 12 Find the mean height.

Mean height =Σ(fi×xi)Σfi=693040=173.25 cm

The heights (in cm ) of 40 boys were measured and recorded and under:

Height (in cm) 165 170 175 180

Number of boys 9 8 11 12

Find the mean height.

Mean height = $\frac{Σ (f_{i} \times x_{i})}{Σ f_{i}} = \frac{6930}{40} = 173.25 cm$