Question

The heights of the two buildings are 34 m and 29 m respectively. If the distance between the two building is 12 m, find the distance between the top of the buildings.

• A. $12m$
• B. $13m$
• C. $16m$
• D. $14m$

Answer 1

The correct option is B

$13m$

The vertical buildings AB and CD are 34 m and 29 m respectively.

Draw DE $\perp$ AB.

Then $AE=AB–EBbutEB=BC$

Therefore $AE=34-29=5m$

Now, AED is a right angled triangle and right angled at E.

Therefore,

$A{D}^2=A{E}^2+E{D}^2$

$A{D}^2=5^2+{12}^2$

$A{D}^2=25+144$

$A{D}^2=169$

$AD=\sqrt{169}$

$AD=13$

Therefore, the distance between the top of the buildings.= $13$ m