wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The Henry's Law constant for Helium, Hydrogen, Nitrogen and Oxygen at 293 K are 144.97 kBar,69.16 kBar,76.48 kBar and 34.86 kBar respectively.
Then which of the following gas will have the highest solubility in water at the given temperature of 293 K and atmospheric pressure?

A
Helium
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Hydrogen
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Nitrogen
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Oxygen
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D Oxygen
Characteristics of Henry’s Law Constant​:
1. Same unit as that of Pressure​
2.Different G-L system have different values of henry's law constant.​
3. It increases with temperature​
4. It depends on intermolecular forces between gas-liquid.​
5. Its value decreases with increase in solubility.
Henry's Law :
p=KH×χ
At a given pressure :
KH1χ
More the value of Henry's law constant, lesser is the solubility of gas inside a given solvent.
Since value of Henry's law constant for oxygen is the least, so it will have the maximum value of solubility or mole fraction (χ)


flag
Suggest Corrections
thumbs-up
4
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon