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Question

The Henry's law constant for the solubility of N2 gas in water at 298 K is 1.0×105 atm. The mole fraction of N2 in air is 0.8. The no. of moles of N2 from air dissolved in 10 moles of water of 298 K and 5 atm pressure is:

A
2×105
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B
6×105
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C
4×104
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D
9×106
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Solution

The correct option is C 4×104
Alc to Henry's law, P=Kxx is the mole fraction k is the Henry's law constant P is partial pressure in atm
Substituing the values, c=41×105=4×105no. of moles of N2 in 10 moles of water n10=4×105n=4×104 mol
Hence ,(C) is correct option.

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