The hero of a stunt film fires 50 g bullets from a machine gun, each at a speed of 1.0 km/s. If he fires 20 bullets in 4 seconds, what average force does he exert against the machine gun during this period.

500 N

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250 N

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100 N

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300 N

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Solution

The correct option is B 250 N
Answer is A.
The momentum of each bullet = (0.050 kg) (1000 m/s) = 50 kg-m/s.
The gun has been imparted this much amount of momentum by each bullet fired. Thus, the rate of change of momentum of the gun
$= \frac{(50 k g - m / s) \times 20}{4 s} = 250 N .$
In order to hold the gun, the hero must exert a force of 250 N against the gun.

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