wiz-icon
MyQuestionIcon
MyQuestionIcon
6
You visited us 6 times! Enjoying our articles? Unlock Full Access!
Question

The hero of a stunt film fires 50 gm bullets from a machine gun, each at a speed of 1.0 km/s. If he fires 20 bullets in 4 s, what average force does he exert against the machine gun during this period?

A
125 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
200 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
250 N
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
400 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 250 N
From Newtons's 2nd law,
F=ΔpΔt=mΔvΔt ...(i)
F= total average force on body
Number of bullets fired, n=20
Change in momentum of each bullet,
mΔv=(50×103 kg)×(1×103 m/s)=50 N.s
Δt=4 s
From Eq (i),
F=n×mΔvΔt
F=20×504
F=250 N

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon