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Question

The hero of a stunt film fires 50 gm bullets from a machine gun, each at a speed of 1.0 km/s. If he fires 20 bullets in 4 s, what average force does he exert against the machine gun during this period?

A
125 N
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B
200 N
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C
250 N
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D
400 N
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Solution

The correct option is C 250 N
From Newtons's 2nd law,
F=ΔpΔt=mΔvΔt ...(i)
F= total average force on body
Number of bullets fired, n=20
Change in momentum of each bullet,
mΔv=(50×103 kg)×(1×103 m/s)=50 N.s
Δt=4 s
From Eq (i),
F=n×mΔvΔt
F=20×504
F=250 N

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