The hero of a stunt film fires 50gm bullets from a machine gun, each at a speed of 1.0km/s. If he fires 20 bullets in 4s, what average force does he exert against the machine gun during this period?
A
125N
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B
200N
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C
250N
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D
400N
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Solution
The correct option is C250N From Newtons's 2nd law, F=ΔpΔt=mΔvΔt...(i) F= total average force on body
Number of bullets fired, n=20
Change in momentum of each bullet, mΔv=(50×10−3kg)×(1×103m/s)=50N.s Δt=4s
From Eq (i), F=n×mΔvΔt ⇒F=20×504 ∴F=250N