Question

The heteroatoms present in ${\mathrm{CH}}_3-{\mathrm{CH}}_2—\mathrm{O}—{\mathrm{CH}}_2—{\mathrm{CH}}_2\mathrm{Cl}$ are (i) oxygen (ii) carbon (iii) hydrogen (iv) chlorine.

• A. (i) and (ii)
• B. (ii) and (iii)
• C. (iii) and (iv)
• D. (i) and (iv)

Answer 1

The correct option is D

(i) and (iv)

Explanation for correct option

(D) (i) and (iv)

• In organic chemistry, heteroatoms are atoms that are not carbon or hydrogen.
• So, the heteroatoms present in ${\mathrm{CH}}_3-{\mathrm{CH}}_2—\mathrm{O}—{\mathrm{CH}}_2—{\mathrm{CH}}_2\mathrm{Cl}$ are Oxygen$\left(\mathrm{O}\right)$, and chlorine$\left(\mathrm{Cl}\right)$.
• In (i) oxygen is present, and in (iv) chlorine is present.

Hence, (i) and (iv) are correct.

Explanation for incorrect option

The heteroatoms present in ${\mathrm{CH}}_3-{\mathrm{CH}}_2—\mathrm{O}—{\mathrm{CH}}_2—{\mathrm{CH}}_2\mathrm{Cl}$ are Oxygen$\left(\mathrm{O}\right)$, and chlorine$\left(\mathrm{Cl}\right)$. Hence, options (A), (B), and (C) are incorrect.

Hence, option (D) is correct. The heteroatoms present in the given compound are oxygen and chlorine.