The hexaaquomanganese (II) ion contains five unpaired electrons while the hexacyano ion contains only one unpaired electron. Explain using Crystal Field Theory.

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Solution

Mn(II) has an electronic configuration of $3 d^{5} 4 s^{0}$ . In the case of hexaaquomanganese (II) ion the ligand attached to metal is water which is a weak field ligand and is not able to pair up the electrons of 3d subshell and the configuration is $t_{2} g^{3}$ and $e g^{2}$ . whereas in the case of hexacyano ion the $C N^{-}$ is a strong field ligand and it causes pairing of electrons in the d orbitals and hence thee exist only one unpaired electron in $t_{2} g^{5}$ $e g^{0}$ .

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