The hexaquo manganese(II) ion contains five unpaired electrons, while the hexacyanoion contains only one unpaired electron. Explain using Crystal Field Theory.

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Solution

Mn is in the +2 oxidation state.

Mn is in the +2 oxidation state.

The electronic configuration is d^5.

The electronic configuration is d⁵.

The crystal field is octahedral. Water is a weak field ligand. Therefore, the arrangement of the electrons in is t2g3eg2.

The crystal field is octahedral. Cyanide is a strong field ligand. Therefore, the arrangement of the electrons in is

T2g5eg0.

Hence, hexaaquo manganese (II) ion has five unpaired electrons, while hexacyano ion has only one unpaired electron.

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Mn is in the +2 oxidation state.	Mn is in the +2 oxidation state.
The electronic configuration is d^5.	The electronic configuration is d⁵.
The crystal field is octahedral. Water is a weak field ligand. Therefore, the arrangement of the electrons in is t2g3eg2.	The crystal field is octahedral. Cyanide is a strong field ligand. Therefore, the arrangement of the electrons in is T2g5eg0.