The highest boiling point is expected for:

isooctane

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n -

octane

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2, 2, 3, 3 -

tetramethyl butane

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n -

butane

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Solution

The correct option is B $n -$ octane

All have the same number of C atoms. n-Octane is a straight-chain compound that has a large surface area. So, there are more van der Waals forces of attraction resulting in a high boiling points.

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Which of the following compounds will give only one isomer on monochlorination

(i)Isopentane (ii) Neopetane (iii) Cyclopentane (iv) 2,2,3,3 - tetramethyl butane (v) n-butane

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2, 2, 3, 3

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