The highest common factor of $48, 92, 132$ is

2

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3

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4

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6

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Solution

The correct option is C $4$
$48 = 2^{4} \times 3$
$92 = 2^{2} \times 23$
$132 = 2^{2} \times 3 \times 11$
The common factor among them is $2^{2} = 4$

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