Question

The highest energy in Balmer series, in the emission spectra of hydrogen is represented by:
$(R_H=109737{cm}^{-1})$

• A. $4389.48{cm}^{-1}$
• B. $2194.74{cm}^{-1}$
• C. $5486.85{cm}^{-1}$
• D. $27434.25{cm}^{-1}$

Answer 1

The correct option is D $27434.25{cm}^{-1}$

$\overline{v}=\frac{1}{\lambda }=R_H{Z}^2[\frac{1}{n_1^2}-\frac{1}{n_2^2}]$

$=109737\times 1^2[\frac{1}{2^2}-\frac{1}{{\infty }^2}]=27434.25{cm}^{-1}$

(series limit will be of highest energy)