The highest number of unpaired electrons are in $F e^{3 +}, F e^{2 +}, F e^{+}$ :

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Solution

The atomic number of iron = $26$

The electronic configuration of $F e^{+}$ = $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{1} 3 d^{6}$
has 5 unpaired electrons.

The electronic configuration of $F e^{2 +}$ = $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{6} 4 s^{0}$
It has 4 unpaired electrons

The electronic configuration of $F e^{3 +}$ = $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{5} 4 s^{0}$
It has 5 unpaired electrons.

So the highest number of unpaired electrons are present in $F e^{3 +}$ .

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(A t o m i c n u m b e r o f F e = 26)

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E_{F e^{3 +} | F e^{2 +}}^{⊖}

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